windows下单机如何配置多个TOMCAT

2018-10-10 17:42 by jewelry, 阅读, 评论, 收藏, 编辑

1、JDK-环境配置:

JAVA_HOME=D:\Program Files\Java\jdk1.7.0_45

CLASSPATH=.;%JAVA_HOME%\lib\dt.jar;%JAVA_HOME%\lib\tools.jar

Path=%JAVA_HOME%\bin;%JAVA_HOME%\jre\bin;

2、免安装版TOMCAT:

TOMCAT1-环境配置

    CATALINA_BASE=D:\Program Files\apache-tomcat-7.0.47

    CATALINA_HOME=D:\Program Files\apache-tomcat-7.0.47

    Path=%CATALINA_HOME%\lib;%CATALINA_HOME%\bin;

conf下server.xml  

    Server port=8006  shutdown=”SHUTDOWN”;

    Connector port=80 protocol=”HTTP/1.1″;

    Connector port=8009 protocol=”AJP/1.3″

TOMCAT2-环境配置

    CATALINA_BASE_7M=D:\Program Files\apache-tomcat-7.0.47-8080

    CATALINA_HOME_7M=D:\Program Files\apache-tomcat-7.0.47-8080

    Path=%CATALINA_HOME_7M%\lib;%CATALINA_HOME_7M%\bin;

bin下catalina.bat、service.bat、shutdown.bat、startup.bat中“CATALINA_BASE”改为“CATALINA_BASE_7M”,“CATALINA_HOME”改为“CATALINA_HOME_7M”

conf下server.xml  

    Server port=8086  shutdown=”SHUTDOWN”;

    Connector port=8080 protocol=”HTTP/1.1″;

    Connector port=8089 protocol=”AJP/1.3″

3、不依赖环境变量中,指定jdk:找到bin下的setclasspath.bat文件;在文件的开始出添加如下代码:

set JAVA_HOME=D:\Program Files\Java\jdk1.8.0_60

set JRE_HOME=D:\Program Files\Java\jre1.8.0_60

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