数据库操作 练习一
- 查看岗位是teacher的员工姓名、年龄
2. 查看岗位是teacher且年龄大于30岁的员工姓名、年龄
3. 查看岗位是teacher且薪资在9000-1000范围内的员工姓名、年龄、薪资
4. 查看岗位描述不为NULL的员工信息
5. 查看岗位是teacher且薪资是10000或9000或30000的员工姓名、年龄、薪资
6. 查看岗位是teacher且薪资不是10000或9000或30000的员工姓名、年龄、薪资
7. 查看岗位是teacher且名字是jin开头的员工姓名、年薪
先创建表格slt:
mysql> create table slt(
-> num int auto_increment primary key,
-> name char(10),
-> job char(10),
-> age int,
-> salary int,
-> descrip char(128)not null default \'\'
-> )charset=utf8;
查看列表
mysql> desc slt;
+---------+-----------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+---------+-----------+------+-----+---------+----------------+
| num | int(11) | NO | PRI | NULL | auto_increment |
| name | char(10) | YES | | NULL | |
| job | char(10) | YES | | NULL | |
| age | int(11) | YES | | NULL | |
| salary | int(11) | YES | | NULL | |
| descrip | char(128) | NO | | | |
+---------+-----------+------+-----+---------+----------------+
6 rows in set (0.02 sec)
此时表为空
mysql> select * from slt;
Empty set (0.00 sec)
插入数据:
mysql> insert into tlt(name, job, age, salary,descrip) values
-> (\'Tom\', \'teacher\', 30, 20000, level2 ),
-> (\'frank\', \'teacher\', 31, 21000, level2 ),
-> (\'jack\', \'teacher\', 32, 22000, level2 ),
-> (\'jhon\', \'asistant\', 23, 8000, \'\' ),
-> (\'hugo\', \'manager\', 45, 30000, level4 ),
-> (\'jinhisan\', \'teacher\', 26, 9000, level1 )
-> ;
Query OK, 6 row affected (0.01 sec)
1、查看岗位是teacher的员工姓名、年龄
mysql> select distinct name, age from slt where job=\'teacher\';
2、查看岗位是teacher且年龄大于30岁的员工姓名、年龄
mysql> select distinct name, age from slt where job=\'teacher\' and age>30;
3、查看岗位是teacher且薪资在1000-9000范围内的员工姓名、年龄、薪资
mysql> select distinct name, age, salary from slt where job=\'teacher\' and (salary>1000 and salary<9000);
4、查看岗位描述不为NULL的员工信息
mysql> select * from slt where descrip!=NULL ;
5、查看岗位是teacher且薪资是10000或9000或30000的员工姓名、年龄、薪资
mysql> select distinct name, age, salary from slt where job=\'teacher\' and (salary=10000 or salary=9000 or salary=30000);
6、查看岗位是teacher且薪资不是10000或9000或30000的员工姓名、年龄、薪资
mysql> select distinct name, age, salary from slt where job=\'teacher\' and (salary not in (10000,9000,30000));
7、查看岗位是teacher且名字是\’jin\’开始的员工姓名、年薪
mysql> select * from slt where job=\'teacher\' and name like \'jin%\' ;