C++中find()函数和rfind()函数的用法
本文转载自http://blog.csdn.net/youxin2012/article/details/9162415
string中 find()的应用 (rfind() 类似,只是从反向查找)
原型如下:
(1)size_t find (const string& str, size_t pos = 0) const; //查找对象–string类对象
(2)size_t find (const char* s, size_t pos = 0) const; //查找对象–字符串
(3)size_t find (const char* s, size_t pos, size_t n) const; //查找对象–字符串的前n个字符
(4)size_t find (char c, size_t pos = 0) const; //查找对象–字符
结果:找到 — 返回 第一个字符的索引
没找到–返回 string::npos
示例:
1 #include <iostream> // std::cout 2 #include <string> // std::string 3 4 int main () 5 { 6 std::string str ("There are two needles in this haystack with needles."); 7 std::string str2 ("needle"); 8 9 // different member versions of find in the same order as above: 10 std::size_t found = str.find(str2); 11 if (found!=std::string::npos) 12 std::cout << "first \'needle\' found at: " << found << \'\n\'; 13 14 found=str.find("needles are small",found+1,6); 15 if (found!=std::string::npos) 16 std::cout << "second \'needle\' found at: " << found << \'\n\'; 17 18 found=str.find("haystack"); 19 if (found!=std::string::npos) 20 std::cout << "\'haystack\' also found at: " << found << \'\n\'; 21 22 found=str.find(\'.\'); 23 if (found!=std::string::npos) 24 std::cout << "Period found at: " << found << \'\n\'; 25 26 // let\'s replace the first needle: 27 str.replace(str.find(str2),str2.length(),"preposition"); //replace 用法 28 std::cout << str << \'\n\'; 29 30 return 0; 31 }
结果:
first \’needle\’ found at: 14
second \’needle\’ found at: 44
\’haystack\’ also found at: 30
Period found at: 51
There are two prepositions in this haystack with needles
其他还有 find_first_of(), find_last_of(), find_first_not_of(), find_last_not_of()
作用是查找 字符串中 任一个字符 满足的查找条件
string snake1(“cobra”);
int where = snake1.find_first_of(“hark”);
返回3 因为 “hark”中 各一个字符 在 snake1–cobra 中第一次出现的是 字符\’r\’(3为 cobra 中\’r\’的索引)
同理:
int where = snake1.find_last_of(“hark”);
返回4 因为 “hark”中 各一个字符 在 snake1–cobra 中最后一次出现的是 字符\’a\’(3为 cobra 中\’r\’的索引)
其他同理
版权声明:本文为cynthia-dcg原创文章,遵循 CC 4.0 BY-SA 版权协议,转载请附上原文出处链接和本声明。