20171108 模拟题 T1
T1
为什么要写这个题呢?
我只是想说:链表也能做!!
QAQAQ
可是……细节什么的考场写的好晕……
(其实我不想解释代码了QAQAQ
Codes:
#include<iostream>
#include<cstring>
#include<cstdio>
#include<algorithm>
using namespace std;
const int N = 100000 + 10;
char s[N];
int ans,ans1,ans2;
int pre[N],nxt[N];
int main(){
//freopen("shower.in","r",stdin);
//freopen("shower.out","w",stdout);
scanf("%s",s + 1);
int len = strlen(s + 1);
for(int i = 1;i <= len;++ i){
pre[i] = i - 1;
nxt[i - 1] = i;
}
nxt[len] = len + 1;
pre[len + 1] = len;
if(s[1] != \'(\') ans ++;
if(s[len] != \')\') ans ++;
s[1] = \'(\',s[len] = \')\';
for(int i = 1;i < len;i = nxt[i]){
if(pre[i] == 0 && s[i] == \')\'){
ans ++;
s[i] = \'(\';
}
if(nxt[i] == len + 1 && s[i] == \'(\'){
ans ++;
s[i] = \')\';
}
if(s[nxt[i]] == \')\' && s[i] == \'(\'){
nxt[pre[i]] = nxt[nxt[i]];
pre[nxt[nxt[i]]] = pre[i];
}
if(s[pre[i]] == \'(\' && s[i] == \')\'){
nxt[pre[pre[i]]] = nxt[i];
pre[nxt[i]] = pre[pre[i]];
}
}
int sum = 0;
for(int i = 0;i < len + 1;i = nxt[i]){
if(s[nxt[i]] == \'(\'){
sum ++;
}
}
cout << ans + (sum / 2) << \'\n\';
return 0;
}
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