上午写了个提CAD PL拐点的程序,很简单,但是遇到提示选择时用esc取消CAD就会报错。程序如下:


代码

using System;

using System.Text;

using Autodesk.AutoCAD.ApplicationServices;

using Autodesk.AutoCAD.Runtime;

using Autodesk.AutoCAD.DatabaseServices;

using Autodesk.AutoCAD.EditorInput;

using Autodesk.AutoCAD.Geometry;

using System.IO;

[assembly:CommandClass(
typeof(提拐点坐标.Class1))]

/*Copyright © 519 2008



AutoCAD version:AutoCAD 2008

Description:



To use 提拐点坐标.dll:



1. Start AutoCAD and open a new drawing.

2. Type netload and select 提拐点坐标.dll.

3. Execute the Test command.



Autodesk references added to this project are acdbmgd.dll,acmgd.dll.
*/



namespace 提拐点坐标

{

/// <summary>

/// Summary for Class1.

/// </summary>

public class Class1:IExtensionApplication

{

public void Initialize()

{

Autodesk.AutoCAD.ApplicationServices.Application.DocumentManager.MdiActiveDocument.Editor.WriteMessage(
"\n调试程序命令GD");//初始化操作

}

public void Terminate()

{

//清除操作

}

Editor ed
= Application.DocumentManager.MdiActiveDocument.Editor;

Database db
= Autodesk.AutoCAD.DatabaseServices.HostApplicationServices.WorkingDatabase;

Autodesk.AutoCAD.DatabaseServices.TransactionManager tm
= Autodesk.AutoCAD.DatabaseServices.HostApplicationServices.WorkingDatabase.TransactionManager;

[CommandMethod(
"GD")]

public void Test()

{

try

{

Transaction trans
= tm.StartTransaction();

using (trans)

{

BlockTable bt
= (BlockTable)trans.GetObject(db.BlockTableId, OpenMode.ForRead);

BlockTableRecord btr
= (BlockTableRecord)trans.GetObject(db.CurrentSpaceId, OpenMode.ForWrite);

PromptSelectionOptions ps
= new PromptSelectionOptions();

ps.MessageForAdding
= "选择要提取的多段线";

TypedValue[] filter
={ new TypedValue(0, "LWPOLYLINE") };

PromptSelectionResult sr
= ed.GetSelection(ps, new SelectionFilter(filter));

if (sr.Status == PromptStatus.OK && sr.Value.Count != 0)

{

StreamWriter sw
= new StreamWriter(@"c://点坐标.txt");

ObjectId[] ss
= sr.Value.GetObjectIds();

foreach (ObjectId obj in ss)

{

Polyline pl
= (Polyline)trans.GetObject(obj, OpenMode.ForRead);

int vn = pl.NumberOfVertices;

for (int i=0; i < vn; i++)

{

Point3d pt3d
= pl.GetPoint3dAt(i);

sw.WriteLine(pt3d.ToString());

}

}

sw.Close();

System.Diagnostics.Process.Start(
"notepad.exe", @"c://点坐标.txt");

}

}

}

finally

{ }

}

}

}

 

主程序没有问题,程序中能报错的地方只有if (sr.Status == PromptStatus.OK & sr.Value.Count != 0)这句,如果选择被取消sr.Status应该为PromptStatus.Cancel,sr.Status == PromptStatus.OK 这句没有问题,如果有问题就可能出现再sr.Value.Count != 0这句。即如果程序判断出sr.Status == PromptStatus.OK为false仍然要执行
sr.Value.Count != 0这句的话CAD就会报错。

查看MSDN上关于“&”的解释为:& 运算符计算两个运算符,与第一个操作数的值无关。

再查看关于“&&”的解释:

x && y

对应于操作

x & y

不同的是,如果 为 false,则不计算 y(因为不论 为何值,“与”操作的结果都为 false)。这被称作为“短路”计算。

不能重载条件“与”运算符,但常规逻辑运算符和运算符 true 与 false 的重载,在某些限制条件下也被视为条件逻辑运算符的重载。


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