等额本息
#include <stdio.h> #include <math.h> #define M 999 int main() { double benjin = 0.0; double lilv = 0.0; double yue_lilv = 0.0; int nianxian = 0; double benxi_a = 0.0; double lixi_a = 0.0; double benjin_yihuan[M] = {0.0}; /*第i个月已还本金*/ double benjin_yu[M] = {0.0}; int yue_a = 0; int i = 0; double yue_benjin[M] = {0.0}; double yue_lixi[M] = {0.0}; double yue_benxi = 0.0; printf("请输入本金 年利率 年限\n"); scanf("%lf%lf%d", &benjin, &lilv, &nianxian); yue_a = nianxian * 12; yue_lilv = lilv / 1200; yue_benxi = benjin * yue_lilv * pow(1 + yue_lilv, yue_a) / (pow(1 + yue_lilv, yue_a) - 1); yue_lixi[0] = benjin * yue_lilv; yue_benjin[0] = yue_benxi - yue_lixi[0]; benjin_yu[0] = benjin - yue_benjin[0]; benjin_yihuan[0] = yue_benjin[0]; printf("第%d个月-应还本金%.2lf\t-应还利息%.2lf\t-剩余本金%.2lf\n", 1, yue_benjin[0], yue_lixi[0], benjin_yu[0]); for (i = 1; i < yue_a; ++i) { yue_lixi[i] = benjin_yu[i-1] * yue_lilv; yue_benjin[i] = yue_benxi - yue_lixi[i]; benjin_yihuan[i] = benjin_yihuan[i-1] + yue_benjin[i]; benjin_yu[i] = benjin - benjin_yihuan[i]; printf("第%d个月-应还本金%.2lf\t-应还利息%.2lf\t-剩余本金%.2lf\n", i+1, yue_benjin[i], yue_lixi[i], benjin_yu[i]); lixi_a += yue_lixi[i]; } benxi_a = lixi_a + benjin + yue_lixi[0]; printf("总本金[%.2lf] 总利息[%.2lf] 总本金利息和[%.2lf]\n", benjin, lixi_a + yue_lixi[0], benxi_a); return 0; }
View Code
版权声明:本文为leegoo原创文章,遵循 CC 4.0 BY-SA 版权协议,转载请附上原文出处链接和本声明。